|
|
|
|
The
sum of the lengths of any two sides of a triangle must be
greater than the
third side. |
|
 |

|
 |
If these inequalities are NOT true, you do
not have a triangle!
 |
 |
Suppose
we know the lengths of two sides of a triangle, and we want to
find the "possible" lengths of the third side. |
| According
to our theorem, the following 3 statements must be true: |
 |
|
5 + x
> 9
So,
x
> 4 |
5 + 9
> x
So,
14 > x |
x + 9
> 5
So,
x
> -4
(no
real information is gained here since the lengths of the sides must
be positive.) |
| Putting
these statements together, we get that
x
must be
greater
than 4,
but
less
than 14.
So any number in the range
4 <
x
< 14 can represent the length of the missing side of our triangle. |
|
|
|
In
a triangle,
the longest side is across from the largest angle. |
|
|
|
|
In a triangle,
the largest angle is across from the longest side. |
|
|
|
|
|
These theorems can be modified to apply to a discussion of only
two angles within the triangle:
Theorem: In a triangle, the
longer side is across from the larger angle.
Theorem: In a triangle, the
larger angle is across from the longer side.
|
Suppose
we want to know which side of this triangle is the longest. |
 |
| Before
we can utilize our theorem, we need to know the size of <B. We
know that the 3 angles of the triangle add up to 180º. |
80
+ 40 + x = 180
120 + x = 180
x = 60 |
|
We have now found that <B measures 60º.
According to our theorem, the longest side will be across from the
largest angle. |
Now
that we know the measures of all 3 angles, we can tell that <A is
the largest. This means the side across from <A,
side , is
the longest side. |
|
|
|
The measure of
the exterior angle of a triangle is greater than the measure of
either nonadjacent interior angle. |
|
|
 |
|

<1 is the exterior angle.
<2 and <3 are its nonadjacent interior angles. |

|
|
Suppose
we are faced with the following proof: |
|
 |
 |
|