Strategies for Dealing with Similar Triangles Topic Index | Geometry Index | Regents Exam Prep Center

 Triangles are similar if their corresponding (matching) angles are congruent (equal in measure) and the ratio of their corresponding sides are in proportion.

 There are many different types of problems that involve similar triangles.  And, fortunately, there are several different ways to arrive at an answer.
 Keep an open mind!  Remember that there may be more than one way to arrive at an answer!

Let's look at some strategies for arriving at answers!

Style 1:  The similar triangles are two separate triangles:

 Find x: Create a proportion matching the corresponding sides. Two possible answers: Small triangle on top: x = 20 Large triangle on top: x = 20 HINT:  These two triangles are sitting such that their corresponding parts are in the same position in each triangle.  If the triangles are not sitting in this manner, you can match the corresponding sides by looking across from the angles which are equal in each triangle.

Style 2:  The similar triangles overlap:

 Many problems involving similar triangles have one triangle ON TOP OF (overlapping) another triangle.  Since is marked to be parallel to , we know that we have

Let's try some problems with this type of diagram:

 Find BE: Read carefully to see WHAT you are supposed to find.  This problem asks you to find BE. Here are two solutions letting BE = x. Use FULL sides of the triangles, cross multiply and solve. 4x + 36 = 12x 36 = 8x 4.5 = x Use the theorem related to parallel lines, cross multiply and solve. 36 = 8x 4.5 = x

 Find EC: This problem asks you to find EC. Here are two solutions letting EC = x: Use FULL sides of the triangles, cross multiply and solve. 32 + 4x = 80 4x = 48 x = 12 Use the theorem related to parallel lines, cross multiply and solve. 4x = 48 x = 12

 Find x: CAREFUL!!! This problem MUST use the full sides of triangles as a solution.  The parallel theorem does not work here.  The problem asks you to find x where x is a FULL side. Here is the solution: x = 5

 HINT: If you have a hard time "seeing" what is happening in overlapping triangles, redraw the triangles as two separate figures.

 Topic Index | Geometry Index | Regents Exam Prep Center Created by Donna Roberts