Example 2:
This problem appears in the Core
Curriculum Resource for Math B.
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Given
f(x) = x2 - 2x
A. Determine an expression for h(x), if
h(x) = f(-x).
B. Determine an expression for g(x), if
g(x) is represented by
the rotation of 180º of f(x)
about the origin.
C. Rotate f(x) 90º about the origin.
Find the coordinates of
the point(s) for which x = -1, under the
rotation. |
Answer:
Things to remember:
•
Rotation of 180º
r180º(x,y) = (-x,-y)• Rotation of
90º
r90º(x,y) = (-y,x)
• Examine points that are easily readable from the
original graph.
• Again, your graphing calculator could assist you
in finding your answers.
• While graphs are NOT required in this problem,
they certainly help in analyzing the problem. |
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The original function, f(x), is graphed in
blue.
A. the expression for h(x) is
h(x) = (-x)2 -2(-x) = x2
+2x
B. the expression
for g(x) is
g(x) = -x2 -2x
C. the 90º
rotation is indicated by the dotted
line. The coordinates for which
x = -1 are (-1, -0.414) and (-1, 2.414)
*
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*
x = -1 under the rotation is equivalent to y = 1
under the original graph.
Therefore, we are interested in x2 - 2x
= 1 which gives x2
-2x -1 = 0
Use your graphing calculator to solve. One possible
calculator solution method is shown below:
Y1=x2 -2x - 1
Y2 = 0
Use 2nd - Calc - #5 Intersect to find the points of
intersection |
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