"I am traveling at a high rate of speed!!
I'm going 5m inches per minute where m equals 10!"

So, at what rate of speed is this little bug
actually traveling in his matchbox cruiser?
Answer:  50 inches per minute


A rate is a ratio that compares two different kinds of numbers, such as miles per hour, or inches per minute.  A unit rate compares a quantity to its unit of measure.

A rate expresses how long it takes to do something.

To drive 50 inches in one minute is to drive at the rate of 50 in./min.

The fraction expressing a rate has units of distance in the numerator and units of time in the denominator. 

Solving a problem dealing with rate usually involves solving a proportion.

Examples:

1.  How long, in minutes, did it take the bug to cover 350 inches at a rate of 50 inches per minute?

  Use "cross multiply" (in a proportion, the product of the means equals the product of the extremes) to solve.
    Answer:   7  minutes

 

2.  The bug drives his matchbox cruiser to his friends house traveling at the rate of 50 inches per minute.  He then walks back to his home at the rate of 10 inches per minute.  If the round trip took 9 minutes, how far is it from the bug's home to his friend's house?
  Distance = Distance
Let t = time

        
        
Distance = Rate x Time
The distance driving the cruiser to the friend's house is the same distance that the bug walks back home = round trip. 

Hint:  We need to first find the time which can then be used to find the distance.

  Answer:  Distance = 50t = 50(1.5) = 75 inches
                         Also 10(9 - t) = 10(9 - 1.5) = 10(7.5) = 75 inches